Question

Write the equation of a line that has a slope of 3 and goes through points (2,1)

Answer 1

The equation of straight line is 3 x-y-5=0

Explanation:

The equation of straight line having slope m = 3 and passing through the point (2,1) is

the standard form of straight line is
`y-y_(1) = m (x-x_(1) )`

now substitute m = 3 and point (2,1) is

`y- 1 = 3(x-2)`

`y - 1 = 3 x - 6`

`3 x-y -6+1=0`

`3 x-y -5 =0`

The equation of straight line is 3 x-y-5=0