Question

How many grams are there in 3.30 x 1023 molecules of N2l6?

Answer 1

432 grams of N₂I₆

Step-by-step explanation:

First we have to divide the given number of molecules (3.3\times10^2^8) by the Avogadro's number of molecules (6.022\times10^2^8), so that we will get the number of moles as 0.5.

Then the 0.5 moles of N₂I₆ is multiplied by the molar mass of N₂I₆ which is 789 g/mol, we will get the mass of N₂I₆ as 432 grams.

So the mass of the N₂I₆ obtained is 432 grams.

`3.30 * 10^2^3molecules / 1 * 1 mol N_2I_6/6.022 *10^2^3 molecules * 789 g / mol/ 1 \ mol N_2I_6 = 432 g\of \ N_2I_6`