Answer:
18/5
Explanation:
let the first term of arithmetic sequence = a and the common difference =d
The first term = a
second term = a + d
third term = a + 2d
fourth term = a + 3d
fifth term = a + 4d
Therefore, the sum of the first five terms = a + (a+d) +(a+2d)+(a+3d)+(a+4d)=5a +10d
The next five terms are
sixth term=a+5d
seventh term=a+6d
eight term=a+7d
ninth term=a+8d
tenth term=a+9d
The sum of the next five terms above=(a+5d)+(a+6d)+(a+7d)+(a+8d)+(a+9d)=5a+35d
The sum of the first five terms is 90 less than the sum of the next five terms
Therefore, 5a+9d+90=5a+35d
90=35d-10d=25d
d=90/25=18/5
Therefore the absolute difference between consecutive terms =18/5