Question

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 81.7 cm and diameter 2.70 cm from a storage room to a machinist. Calculate the weight of the rod, w. The acceleration due to gravity, g

Answer 1

35.792 N

Step-by-step explanation:

d = Diameter of rod = 2.7 cm

h = Length of rod = 81.7 cm

`\rho` = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

`V=(1)/(4)\pi d^2h\\\Rightarrow V=(1)/(4)* \pi* (2.7* 10^(-2))^2* 81.7* 10^(-2)`

Mass is given by

`m=\rho V\\\Rightarrow m=7800* (1)/(4)* \pi* (2.7* 10^(-2))^2* 81.7* 10^(-2)\\\Rightarrow m=3.6486\ kg`

Weight is given by

`W=mg\\\Rightarrow W=3.6486* 9.81\\\Rightarrow W=35.792\ N`

The weight of the rod is 35.792 N