Question

Spheres of Charge: A metal sphere of radius 10 cm carries an excess charge of +2.0 μC. What is the magnitude of the electric field 5.0 cm above the sphere's surface? (k = 1/4πε0 = 9.0 × 10^9 N ∙ m^2/C^2)

Answer 1

To solve this problem we will apply the concept related to the electric field. The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,

`E = (kV)/(r^2)`

Here,

k = Coulomb's constant

V = Voltage

r = Distance

Replacing we have

`E = ((9*10^9)(2*10^(-6)))/(((10+5)*10^(-2))^2)`

`E = 8*10^5N/C`

Therefore the magnitude of the electric field is
`8*10^5N/C`