Final answer:
The two numbers in question can be found by setting up a system of equations, simplifying and solving them to get the first number as 30 and the second number as 20.
Step-by-step explanation:
The student's question involves finding two numbers given a system of equations. The conditions provided are that the sum of two numbers is 50, and three times the first number minus three times the second number is 30. To solve this, let x be the first number and y be the second number. We then have the following equations:
x + y = 50
3x - 3y = 30
To solve for x and y, we can simplify the second equation by dividing everything by 3, giving us x - y = 10. Now we have two equations:
x + y = 50
x - y = 10
We can solve these equations by adding them together, which will eliminate y and give us 2x = 60. Dividing by 2, we get x = 30. To find y, we substitute x into the first equation: 30 + y = 50, which gives us y = 20. Therefore, the two numbers are 30 and 20.