Question

Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alchoholic fermentation. The net reaction isC6H12O6------2C2H5OH(l) +2CO2(g)Calculate the mass of glucose required to produce 2.25L of CO2 measured at P=1 atm and T=295k

Answer 1

8.37 grams

Step-by-step explanation:

The balanced chemical equation is:

C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)

Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.

From the ideal gas law we can determine the number of moles that the 2.25 L represent.

From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.

PV = nRT ⇒ n = PV/RT

n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂

Moles glucose required:

0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

0.046 mol x 180.16 g/mol = 8.37 g