Answer:
60 pounds of skimmed milk to be removed
Explanation:
Given that 300 pounds of milk is testing 3 % of milk
It means;
3% of fats = 300 pounds of milk
or
1% of fats = 100 pounds of milk -------------(1)
Now let x% of fat be added to present value of fats so that it becomes 3.6% of fats
i-e
x+3=3.6
this gives x=0.6% of fats needs to be increased
but from eq (1) we know
1% of fats =100 pounds of milk
so, 0.6% of fats = 0.6x100=60 pounds of skimmed milk is to be removed .