Question

B-2a^2/b^2-a/b^2-a where a=-3 and b=-1 answer should be in a improper fraction, if appropriate.

Answer 1

`\Rightarrow -(73)/(4)`

Explanation:

The given expression,
`(b-2a^2)/(b^2)-(a)/(b^2-a)`

where, a = -3 and b = -1

Put the value of a and b into expression

`\Rightarrow ((-1)-2(-3)^2)/((-1)^2)-((-3))/((-1)^2-(-3))`

Simplify each parentheses

`\Rightarrow (-1-18)/(1)+(3)/(1+3)`

`\Rightarrow -19+(3)/(4)`

Now make same denominator

`\Rightarrow -(76)/(4)+(3)/(4)`

`\Rightarrow (-76+3)/(4)`

`\Rightarrow -(73)/(4)`

This is improper fraction because numerator is greater than denominator.