Question

In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is?

A)Reduced by half.
B)doubled.
C)increased by half.
D)left changed.

Answer 1

The pressure of the gas is:

Doubled

Step-by-step explanation:

Byole's Law = Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.

PV = k = constant

P1V1 = P2V2

Charle's Law: The volume of ideal gas at fixed pressure is directly proportional to Pressure.

V/T = constant

V1/T1 = V2/T2

On combinig the charles and byole's law , we get:

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`

Now , According to question :

V2 = V1

T2 = 2(T1)

We have to find the relation between the pressure :

insert the value in the equation

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(1))/(2T_(1))`

V1 and V1 & T1 and T1 cancels each other,

So we get

P2 = 2 P1

So the new pressure is double of the original pressure