Answer:
Option 2) 2x3 – 6x2 – 14x + 24 square centimeters
Explanation:
We know the Parallelogram Area is given by
Eqn. (1)
where
: is the base
: is the height
We are also given that the base is
![b=2x^2+2x-6](https://img.qammunity.org/2021/formulas/mathematics/high-school/wolsweml794zradf6rye8s4suqyur5ytvn.png)
and the height is
![h=x-4](https://img.qammunity.org/2021/formulas/mathematics/high-school/rw6416moao7hp383ly6284uhgjtf6n1whx.png)
So we can plug these two expressions in Eqn. (1), simplify and find our Area equation as follow:
![A=(2x^2+2x-6)(x-4)\\\\A=(2x^2)(x)+(2x)(x)-(6)(x)+(2x^2)(-4)+(2x)(-4)-(6)(-4)\\\\A=2x^3+2x^2-6x-8x^2-8x+24\\\\A=2x^3+2x^2-8x^2-6x-8x+24\\\\A=2x^3-6x^2-14x+24](https://img.qammunity.org/2021/formulas/mathematics/high-school/xx60vqqhg2h1hazk2rv8iffbdsdffu3l2g.png)
Which matches Option 2. from the available ones.