Question

Suppose that the electric field in the Earth's atmosphere is E = 1.16 102 N/C, pointing downward. Determine the electric charge in the Earth. (The radius of the Earth is 6371 km, and the Coulomb's constant,

Answer 1

Electric charge in the earth will be
`Q=5.231* 10^5C`

Step-by-step explanation:

We have given that E = 116 N/C

Radius of the earth R = 6371 km = 6371000 m

We have to find the electric charge in the earth '

We know that electric field due to charge is given by
`E=(1)/(4\pi \epsilon _0)(Q)/(R^20)=(KQ)/(R^2)`. here K is coulomb's constant

So
`116=(9* 10^9* Q)/((6371000)^2)`

`Q=5.231* 10^5C`

So electric charge in the earth will be
`Q=5.231* 10^5C`