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Solving a right triangle (round to the nearest tenth)

Solving a right triangle (round to the nearest tenth)-example-1

1 Answer

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Answer:

see explanation

Explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

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tan46° =
(opposite)/(adjacent) =
(b)/(23)

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

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cos46° =
(adjacent)/(hypotenuse) =
(23)/(c)

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c =
(23)/(cos46) ≈ 33.1 ( to the nearest tenth )

User PRIYA PARASHAR
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