Question

Find the magnitude of the electric field at a point 0.120 mm outside the surface of the sphere. Express your answer in newtons per coulomb.

Answer 1

The magnitude of the electric field at a point outside a charged sphere is calculated using the formula E = kQ/r². Without the specific charge of the sphere, the calculation cannot be completed.

Step-by-step explanation:

To calculate the magnitude of the electric field at a point outside the surface of a spherical charge distribution, you can use the formula E = kQ/r², where E is the electric field magnitude, k is Coulomb's constant (8.99 x 10⁹ Nm²/C²), Q is the charge, and r is the distance from the charge to the point of interest.

However, since the charge Q is not given in the question, I am unable to provide a numerical answer. The correct approach to find the answer would involve substituting the given numerical values into the formula once the charge is known. For example, if the sphere had a charge of 2.00 nC and the point of interest was 0.120 mm away, the calculation would be E = (8.99 x 10⁹ Nm²/C²)(2.00 x 10⁻⁹ C)/(0.120 x 10⁻⁳ m)².

Answer 2

So, if the sphere has net amount of charge on it, such that the test charge will experience its intensity in the given region of influence. As, the charge particles size plays a very important role in this regards, as the total distribution of the net charge occurs on the surface of the sphere.

So, we have the following formula in order to make the calculations and have the results, which is as follows:

• E=F/q, (while "F" is the net amount of force applied by the charged body when the test charge,q is placed in its field)
• And if we analyze the Gauss's law we have, Ф=q/∈,
• While, we can obtain the required results by putting all the data into the following equation,as follows:
• E=kq/r².