Answer:
E = 4.75 x 10⁻¹⁶ J
Step-by-step explanation:
given,
wavelength of the x-ray , λ = 4.18 Å
Energy of photon = ?
we know
![E = (hc)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/college/dkczon6f38n9ku7k22kz1hsninriokdj0d.png)
where h is the planks constant
c is the speed of light
h = 6.626 x 10⁻³⁴ m² kg / s
c = 3 x 10⁸ m/s
now,
![E = (6.626* 10^(-34)* 3 * 10^8)/(4.18* 10^(-10))](https://img.qammunity.org/2021/formulas/physics/college/yst47vik9mfflsmzgd13d9h48b53ovwj1i.png)
E = 4.75 x 10⁻¹⁶ J
hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J