Answer:
52,891.735 cy
Step-by-step explanation:
Data provided in the question:
Net volume of the soil excavated = 50,000 cy = 50,000 × 27 ft³
Dry weight of the soil = 110 pcf
Moisture content = 18%
Unit weight of soil at borrow site, γ = 120 pcf
Water content ratio, w = 15.4% = 0.154
Thus,
Weight of sold required = Dry weight × Net volume of the soil excavated
= 110 × 50,000 × 27
= 148,500 kips
Dry density of soil at borrow site =
![(\gamma)/(1+w)](https://img.qammunity.org/2021/formulas/engineering/college/u0xu7bzruf2odxoka6j7qge6flaszmy6xr.png)
=
![(120)/(1+0.154)](https://img.qammunity.org/2021/formulas/engineering/college/qvvx1aa99lkbj6m8l6ipta1og7t6skphwn.png)
= 103.986 pcf
Therefore,
The volume of soil required = weight ÷ Density
= [ 148,500 × 10³ ] ÷ 103.986
= 1428076.857 cft
or
= 1428076.857 ÷ 27 cy
= 52,891.735 cy