Question

If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution, what is the concentration of sodium chloride in the diluted solution? A) 0.250 MM B) 1.13 M C) 0.500 M D) 0.450 M E) none of the above

Answer 1

D) 0.450 M

Step-by-step explanation:

Given data

• Initial volume (V₁): 6.00 mL

• Initial concentration (C₁): 0.750 M

• Volume of water (VH₂O): 4.00 mL

• Final volume (V₂): V₁ + VH₂O = 6.00 mL + 4.00 mL = 10.0 mL

• Final concentration (C₂): ?

We can determine the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.750 M × 6.00 mL/10.0 mL

C₂ = 0.450 M