Question

A solution contains 180 g of glucose (C6H12O6) and 162 g of water. What is the mole fraction of glucose?

Answer 1

0.10

Step-by-step explanation:

Answer 2

0.1 is the mole fraction of glucose.

Step-by-step explanation:

Mas of glucose = 180 g

Moles of glucose =
`n_1=(180 g)/(180 g/mol)=1`

Mass of water = 162 g

Moles of water =
`n_2=(162 g)/(18 g/mol)=9 mol`

Mole fraction of glucose =
`\chi_1`

`\chi_1=(n_1)/(n_1+n_2)=(1 mol)/(1 mol+9 mol)=0.1`

0.1 is the mole fraction of glucose.