Question

A 7.94 nC charge is located 1.79 m from a 4.06 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other. N (b) Is the force attractive or repulsive? attractive repulsive

Answer 1

`9.044824943* 10^(-8)\ N`

repulsive

Step-by-step explanation:

k = Coulomb constant =
`8.99* 10^(9)\ Nm^2/C^2`

`q_1` = 7.94 nC

`q_2` = 4.06 nC

r = Distance between the particles = 1.79 m

Electrical force force is given by

`F=(kq_1q_2)/(r^2)\\\Rightarrow F=(8.99* 10^(9)* 7.94* 10^(-9)* 4.06* 10^(-9))/(1.79^2)\\\Rightarrow F=9.044824943* 10^(-8)\ N`

The magnitude of the electrostatic force is
`9.044824943* 10^(-8)\ N`

Both the paricles have positive charges this means they will repel each other.