Question

You launch a baseball through the air at speed 37 m/sec, at angle 45 degrees above horizontal. Neglect air resistance. What shape is the trajectory?

Answer 1

Parabolic motion

Step-by-step explanation:

It is given that,

Speed with which a baseball is launched through the ar, v = 37 m/s

Angle of projection,
`\theta=45^(\circ)`

We know that when an object is projected with some initial speed having some angle of projection, the path followed by the object is called projectile motion. The object will act as a projectile here. As a result the shape of the trajectory will be parabolic.

The equation of parabolic path is given by :

`y=tan\theta\ x-(gx^2)/(2u^2\ cos^2\theta)`

It is similar to,

`y=ax+bx^2` which is the equation of parabola

Hence, this is the required solution.