Question

How to find the parallel line to y= negative 3X +5 and has a X intercept of three

Answer 1

Therefore, equation of the line that passes through (3,0) and is parallel to the line

`y=-3x+5`

is

`y=-3x+9`

Explanation:

Given:

`y=-3x+5` ...Equation of line

The require line is Parallel to above line and has a X -intercept of three,

i.e y-coordinate will be zero and x-coordinate is 3 ,therefore the point

is ( 3 , 0 )

To Find:

Equation of line passing through ( 3, 0) and is parallel to the line y=-3x+5

Solution:

`y=-3x+5` ...........Given

Comparing with,

`y=mx+c`

Where m =slope

We get

`Slope = m = -3`

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (3 , 0) will also have the slope = m = -3.

Now the equation of line in slope point form given by

`(y-y_(1))=m(x-x_(1))`

Substituting the points and so we will get the required equation of the line,

`(y-0)=-3(x-3)=-3x+9\\\\y=-3x+9......Equation\ of\ line`

Therefore, equation of the line that passes through (3,0) and is parallel to the line

`y=-3x+5`

is

`y=-3x+9`