Answer:
aluminum bar carrying a higher load than steel bar
Step-by-step explanation:
Given data;
steel abr
diameter = 5 mm
stress = 500 MPa
aluminium bar
diameter = 10 mm
stress = 150 MPa
we know
stress = laod/area
for steel bar
![500 = (P)/((\pi)/(4) 5^2)](https://img.qammunity.org/2021/formulas/engineering/college/uvr5ewm39t8qscxoby1hhj4jozreyvrorz.png)
solving for P
P = 9817.47 N
for Aluminium bar
![150 = (P)/((\pi)/(4) 10^2)](https://img.qammunity.org/2021/formulas/engineering/college/qlo29jz50nlv1nx6f1hlizfoo1f6nd4hns.png)
solving for P
P = 11790 N
aluminum bar carrying a higher load than steel bar