Answer:
0.176 m/s
Step-by-step explanation:
given,
mass of the puck, m = 170 g
Length of the ramp, L = 3.6 mm
angle of inclination, θ = 26°
the minimum speed require to reach at the top of the ramp
using equation of motion
v² = u² + 2 a s
final speed of the puck is zero
0² = u² - 2 g s
![u = √(2gh)](https://img.qammunity.org/2021/formulas/physics/high-school/men00n5e1f26clbft66t6o3307ui87vkwk.png)
height of the pluck
![sin \theta = (h)/(L)](https://img.qammunity.org/2021/formulas/physics/high-school/tzgfrmgasg0jpajd3j9us33ahhvo9xlih4.png)
![sin 26^0= (h)/(3.6)](https://img.qammunity.org/2021/formulas/physics/high-school/wy9oevn7t5mxe7ijksdnuunnqxnavl6m2e.png)
h = 1.58 mm
h = 0.00158 m
now,
![u = √(2* 9.8* 0.00158)](https://img.qammunity.org/2021/formulas/physics/high-school/8dx6b3zk6wt3p95qixonhx5wx4xv0vui2g.png)
u = 0.176 m/s
hence, the speed required by the pluck to reach at the top is equal to 0.176 m/s