Question

A student moves 8.0 m to the west, 6.0 m to the north, and 10.0 m to the east. What is the magnitude of the displacement?

Answer 1

Magnitude of displacement is 6.32 m

Step-by-step explanation:

Let east be positive x axis and north be positive y axis.

A student moves 8.0 m to the west, 6.0 m to the north, and 10.0 m to the east.

8 m to west = -8 i

6 m to north = 6 j

10 m to east = 10 i

Total displacement = -8 i + 6 j + 10 i

Total displacement = 2 i + 6 j

`\texttt{Magnitude = }√(2^2+6^2)\\\\\texttt{Magnitude = }6.32m`

Magnitude of displacement is 6.32 m