Question

(3y-4y+1)+(Negative Y to the power of 2+ Y -2

Answer 1

`(3y - 4 y +1)+(-y)^2+y-2`
`=(y+1)(y-1)`

Explanation:

Given that

`(3y - 4 y +1)+(-y)^2+y-2`

`=(-y+1) + y^(2) +y-2`

`=-y +1+y^(2) +y -2`

`=y^(2) - 1`

`= y^2 -(1)^2`

`=(y+1)(y-1)`