Question

How much work must be done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle)?

Answer 1

`Potential\ Energy=Work \ Done=2.301*10^(-18) J`

Work done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is
`2.301*10^(-18) Joules`

Step-by-step explanation:

The potential energy is given by:

U=Q*V

where:

Q is the charge

V is the potential difference

Potential Difference=V=
`(kq)/(r)`

So,

`Potential\ Energy=(Qkq)/(r) \\Q=q\\Potential\ Energy=(kq^2)/(r)`

Where:

k is Coulomb Constant=
`8.99*10^9 Nm^2/C^2`

q is the charge on electron=
`-1.6*10^-19 C`

r is the distance=
`3.0*10^(-10)m`

For 3 Electrons Potential Energy or work Done is:

`Potential\ Energy=3*(kq^2)/(r)`

`Potential\ Energy=3*((8.99*10^9)(-1.6*10^(-19))^2)/(3*10^(-10))\\Potential\ Energy=2.301*10^(-18) J`

Work done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is
`2.301*10^(-18) Joules`