Question

Two particles, one with charge − 7.97 × 10 − 6 C and the other with charge 2.71 × 10 − 6 C , are 0.0359 m apart. What is the magnitude of the force that one particle exerts on the other?

Answer 1

150.83 N

Step-by-step explanation:

From coulomb's law,

F = kqq'/r²............................. Equation 1

Where F = force between the particles, q = charge on the first particle, q' = charge on the second particle, r = distance between the particles, k = proportionality constant.

Given: q = 7.97×10⁻⁶ C, q' = 2.71×10⁻⁶ C, r = 0.0359 m.

Constant: k = 9.0×10⁹ Nm²/C²

Substitute into equation 1

F =(9.0×10⁹)( 7.97×10⁻⁶)(2.71×10⁻⁶ )/0.0359²

F = 194.3883×10⁻³/0.0012888

F = 150828.91×10⁻³

F = 150.83 N.

Hence the magnitude of the force that one particle exert on the other = 150.83 N