Answer:
The four consecutive even integers are 4, 6, 8 and 10.
Explanation:
Let the four consecutive even integers be
![x, x+2, x+4, x+6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/uguwtq8lqoomum5kku794qjn7km1tl06l6.png)
It is provided that the sum of these consecutive even integers is 28.
Solve for x as follows:
![x+ x+2+ x+4+ x+6=28\\4x+12=28\\4x=16\\x=4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hlaa4gx2u16cbav2c4fr9opgv03qv1wuqe.png)
The four consecutive even integers are:
![x=4\\x+2=4+2=6\\x+4 = 4 +4 =8\\x+6=4+6=10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/36hg5w8b5xkr6s5bt9d9xka8he36j8djkt.png)
Thus, the four consecutive even integers are 4, 6, 8 and 10.