Question

Dave ordered dinner for a party of 10 people. Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each. what was the average cost of each dinner at Dave's party?

Answer 1

The average cost of each dinner at Dave's party is $5.79.

Explanation:

Given:

Dave ordered dinner for a party of 10 people.

Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.

Now, to find the average cost of each dinner at Dave's party.

So, we get the total amount for the dinner:

Three people ordered the $4.75 chicken dinner.

`4.75* 3=14.25`

Two people ordered the $4.95 fish dinner.

`4.95* 2=9.90`

Five had the beef dinner at a cost of $6.75.

`6.75* 5=33.75`

Total amount of dinner =
`14.25+9.90+33.75=\$57.90.`

Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:

`57.90/ 10`

`=\$5.79.`

Therefore, the average cost of each dinner at Dave's party is $5.79.