Question

What is the electric field 3.3 m from the center of the terminal of a Van de Graaff with a 7.20 mC charge, noting that the field is equivalent to that of a point charge at the center of the terminal?

Answer 1

Electric Field is
`5.943801*10^6 N/C`

Step-by-step explanation:

Electric Field:

It originates from positive charge and ends at negative charge.

General Formula for electric Field:

`E=(kq)/(r^2)`

where:

k is the Coulomb Constant

q is the charge

r is the distance

Given:

q=7.20 mC

r=3.3 meters

k=
`8.99*10^9 N.m^2/C^2`

Find:

Electric Field=?

Solution:

`E=(kq)/(r^2)`

`E=((8.99*10^9)(7.20*10^(-3)))/(3.3^2)\\E=5943801.653 N/C\\E=5.943801653*10^6 N/C`

Electric Field is
`5.943801*10^6 N/C`