Question:
The second of two numbers is 4 times the first. Their sum is 45. Find the numbers
Answer:
The two numbers are 9 and 36
Solution:
Let the two numbers be "x" and "y"
Let "x" be the first number and "y" be the second number
Given that the sum of numbers is 45
x + y = 45 ------- eqn 1
Also, given that, second of two numbers is 4 times the first
second number = 4 times the first
y = 4x ------- eqn 2
Substitute eqn 2 in eqn 1
x + 4x = 45
5x = 45
x = 9
Substitute x = 9 in eqn 2
y = 4(9)
y = 36
Thus the two numbers are 9 and 36