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Envision two areas of a cell separated by a membrane permeable to glucose. Glucose is at a higher concentration in area "A" than area "B". In which direction is at thermodynamically favorable for glucose to move? A) from area A to area B B) from area B to area A C) both directions are favorable D) both directions are unfavorable

User Maidi
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2 Answers

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Final answer:

Glucose would A) move from area A to area B. When the concentration of glucose is equal, there would be no net flow of glucose across the cell membrane.

Step-by-step explanation:

The thermodynamically favorable direction for glucose to move in this scenario would be from area A to area B. This is because the glucose concentration is higher in area A than in area B, therefore there is a concentration gradient thus favoring the movement of glucose from the higher concentration area (A) to the lower concentration area (B).

When the concentration of glucose is equal inside and outside of the cell, there would be no net flow of glucose across the cell membrane in either direction. This is because there is no proper concentration gradient driving the movement of glucose.

User Leisha
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Answer: option B

The fact that is thermodynamically favourable shows that it involves the expenditure of heat.Then energy must have been consumed as ATPs, for the transport to occur.Thus active transport is needed, to move the glucose against the concentration gradient from area B of lower concentration to A of high concentration.

Basically the transport of substances with the use of ATPs from medium of lower concentration to medium of higher concentration against the concentration gradient is called Active transport.Heat energy is liberated from the expenditure of energy.

Step-by-step explanation:

User Dylan Copeland
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