Answer:
The answer to your question is 0.3 g of H₂
Step-by-step explanation:
Data
N₂ (g) = 1.4 g
H₂ (g) = ?
Balanced Reaction
N₂(g) + 3H₂ (g) ⇒ 2NH₃ (g)
Process
1.- Calculate the atomic mass of nitrogen and hydrogen.
N₂ = 14 x 2 = 28 g
H₂ = 1 x 6 = 6 g
2.- Use proportions and cross multiplication to solve it
28 g of N₂ ------------------- 6 g of H₂
1.4 g of N₂ -------------------- x
x = (1.4 x 6) / 28
x = 0.3 g of Hydrogen