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A hypothetical square shrinks at a rate of 49 squared meters per minute. At what rate are the sides of the square changing when the sides are 13m each?

User Npatel
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1 Answer

4 votes

Answer:

-3.769 m/min

Step-by-step explanation:


(dA)/(dt) = Rate of change of area = -49 m²/min (negative due to shrinking)

s = Side length = 13 m


(ds)/(dt) = Rate of change of side

Area of a square is given by


A=s^2

Differentiating with respect to time


(dA)/(dt)=(ds^2)/(dt)\\\Rightarrow (dA)/(dt)=2s(ds)/(dt)\\\Rightarrow (ds)/(dt)=(dA)/(dt)* (1)/(2s)\\\Rightarrow (ds)/(dt)=-49* (1)/(13)\\\Rightarrow (ds)/(dt)=-3.769\ m/min

The rate of change of the sides of the square is -3.769 m/min

User Scwagner
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