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Solving a right triangle (ROUND TO THE NEAREST TENTH)

Solving a right triangle (ROUND TO THE NEAREST TENTH)-example-1
User Jesse Bunch
by
2.7k points

1 Answer

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1 vote

Answer:

see explanation

Explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 40)° = 180° - 130° = 150°

--------------------------------------------------------------

sin40° =
(opposite)/(hypotenuse) =
(a)/(21)

Multiply both sides by 21

21 × sin40° = a, thus

a ≈ 13.5 ( to the nearest tenth )

--------------------------------------------------------------

cos40° =
(adjacent)/(hypotenuse) =
(b)/(21)

Multiply both sides by 21

21 × cos40° = b, thus

b ≈ 16.1 ( to the nearest tenth )

User Nidin Vinayakan
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2.9k points