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Solving a right triangle (round to the nearest tenth) ‼️‼️‼️

Solving a right triangle (round to the nearest tenth) ‼️‼️‼️-example-1
User Drobison
by
4.9k points

1 Answer

4 votes

Answer:

see explanation

Explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 47)° = 180° - 137° = 43°

-------------------------------------------------------------

tan47° =
(opposite)/(adjacent) =
(a)/(14)

Multiply both sides by 14

14 × tan47° = a, thus

a ≈ 15.0 (to the nearest tenth )

---------------------------------------------------------------

cos47° =
(adjacent)/(hypotenuse) =
(14)/(c)

Multiply both sides by c

c × cos47° = 14 ( divide both sides by cos47° )

c =
(14)/(cos47) ≈ 20.5 ( to the nearest tenth )

User Zahidur Rahman
by
5.0k points