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A fair 6-sided die is rolled 10 times (each roll is independent). What is the probability that the rolled die will not show an even number? (That every roll is odd)

User Antjanus
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Answer:

1/1024.

Explanation:

There are 3 odd numbers in the numbers from 1 to 6. So:

Probability (one toss is odd) = 3/6 = 1/2.

So the Probability ( 10 tosses are all odd) = (1/2)^10

= 1/1024.

User Dannyyy
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