Question

At the instant when the electron is 4.40 cmcm from the wire and traveling with a speed of 6.10×104 m/sm/s directly toward the wire, what is the magnitude of the force that the magnetic field of the current exerts on the electron?

Answer 1

The force that the magnetic field of the current exerts on the electron is
`2.30*10^(-19)\ N`

Step-by-step explanation:

Given that,

Distance = 4.40 cm

Speed
`v= 6.10*10^(4)\ m/s`

Suppose a long, straight wire carries a current of 5.20 . An electron is traveling in the vicinity of the wire.

We need to calculate the magnetic field of the current exerts on the electron

Using formula of force

`F=qv* B`

`F=qv*(\mu_(0)I)/(2\pi r)`

Put the value into the formula

`F=1.6*10^(-19)*6.10*10^(4)*(4\pi*10^(-7)*5.20)/(2\pi*4.40*10^(-2))`

`F=2.30*10^(-19)\ N`

Hence, The force that the magnetic field of the current exerts on the electron is
`2.30*10^(-19)\ N`