Question

When you do this please show the work

Answer 1

2)
`\displaystyle -9a^3b^5`

1)
`\displaystyle (x^8)/(3)`

Step-by-step Step-by-step explanation:

2)
`\displaystyle ((27a^3b^3)(-2ab^4))/(6ab^2) \Rightarrow ((3ab)^3(-2ab^4))/(6ab^2) \\ \\ \boxed{-9a^3b^5} \rightarrow (-54a^4b^7)/(6ab^2)`

1)
`\displaystyle (16x^(10)y^2)/(48x^2y^2) \Rightarrow ((-4x^5y)^2)/(48x^2y^2) \\ \\ \boxed{(x^8)/(3)}`

The Quotient-to-Power Rule states that whenever you are dividng like-terms, you keep the coefficients and deduct the exponents.

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