Answer:
Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because
![9+12\\eq 15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wtcgrlsvxjz2pqwe5t2biy69fot1phsq5n.png)
Explanation:
The complete question in the attached figure
we know that
If the length sides of a triangle, satisfy the Pythagorean Theorem, then is a right triangle
![c^2=a^2+b^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/byhrr90olo1xo4n215kg0bc367cjwlvx2c.png)
where
c is the hypotenuse (the greater side)
a and b are the legs
In this problem
The length sides squared of the triangle are equal to the areas of the squares
so
![a^2=12\ in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lsevgbmdt8m1pg91nzmvkv2hx40isnuvb4.png)
![b^2=9\ in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2h78dpflg6woj6a9iakwicx0tu41jwekve.png)
substitute
![15=12+9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8np89gm6bld52rehbzkgbp45594o1asrcf.png)
----> is not true
so
The length sides not satisfy the Pythagorean Theorem
therefore
Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because
![9+12\\eq 15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wtcgrlsvxjz2pqwe5t2biy69fot1phsq5n.png)