Question

A(n) 6.76 mL sample of water is cooled from 39.5°C to 13.6°C. How many joules of energy are absorbed or released by the water? (Use a negative sign if the water is releasing heat.) The specific heat capacity of liquid water is 4.184 J/g • K.

Answer 1

-732.5 5 Joules

Step-by-step explanation:

This a typical calorimetry problem that can be solved with the formula:

Q = m . C . ΔT

First of all, we determine the mass of water, by density.

Density is mass /volume

1 g/mL = mass / 6.76 mL → 6.76 g

Q = 6.76 g . 4.184 J/g°C . (13.6°C - 39.5°C)

Q = -732.5 5 Joules

Water is releasing heat to be cooled, that's why the answer is negative.