(i) The area of the sheet required is 5.45
![m^2.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qp3hbayq47po3shqbwm3y0p692qgi32uoi.png)
(ii) Cost of the sheet is Rs 109.
Solution:
Given length of the box (l) = 1.5 m
breadth of the box (b) = 1.25 m
depth of the box (h) = 65 cm =
= 0.65 m
Top of the box is open.
(i) To find the area of the sheet required.
Area of the sheet required = Surface area of cuboid – Area of top
= 2(lb + bh + lh) – lb
= 2(1.5 × 1.25 + 1.25 × 0.65 + 1.5 × 0.65) – (1.5 × 1.25)
= 2(1.875 + 0.8125 + 0.975) – 1.875
= 2(3.6625) – 1.875
= 7.325 – 1.875
= 5.45 sq. m
Thus, area of the sheet required is 5.45
![m^2.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qp3hbayq47po3shqbwm3y0p692qgi32uoi.png)
(ii) To find the cost of the sheet.
Cost of sheet per 1
= Rs 20
Cost of sheet of 5.45
= Rs (5.45 × 20) = Rs 109
Hence (i) The area of the sheet required is 5.45
![m^2.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qp3hbayq47po3shqbwm3y0p692qgi32uoi.png)
(ii) Cost of the sheet is Rs 109.