Question

How many atoms and ions does lithium sulfite have?

Answer 1

Hence the ions per mole are:

`Li^(+)= 2 ions`

`SO_(3)^(2-)(aq)= 1 ions`

In one mole of Li2SO3 , the number of the atoms are

`N_(a)=6.022* 10^(23)`

Step-by-step explanation:

The formula of lithium sulfite is Li2SO3.

`Li_(2)SO_(3)`

It contain Li+ and SO3(2-) ions.This can be represented by :

`Li_(2)SO_(3)(s)\rightarrow 2Li^(+)(aq) +SO_(3)^(2-)(aq)`

Hence one mole of Li2SO3 will give 2 Li+ ions and 1 SO3 (2-) ion.

Hence the ions per mole are:

`Li^(+)= 2 ions`

`SO_(3)^(2-)(aq)= 1 ions`

Number of atoms in lithium sulfite depends upon the mass of the Li2SO3 present .

Li2SO3 = 93.94 g/mole

This mass is equal to 1 mole of Li2SO3

Now 1 mole of any substance contain Na atoms . This is known as Avogadro Number.

`N_(a)=6.022* 10^(23)`

Hence , if 1 mole of Li2SO3 is present then it contains Na atoms

If other then 1 mole present then number of atoms are calculated by:

`Number\ of\ Atoms=Moles* (N_(a))`

Here n = number of moles

if the mass of the compound is given then first calculate the number of moles.

`Moles=(mass)/(Molar\ mass)`