Question

What is the solution to the system of equations?

(3x+2y = 39
(5x-y=13
O (4,7)
O (7,4)
O (12,5)
(5, 12)

Answer 1

X = 5

Y= 12

Explanation:

3x + 2y = 39 —> (1)

5x - y = 13 —> (2)

Multiply (2) with 2

10x - 2y = 26 —> (b)

(1) + (b)

This will eliminate the y factor, leaving:

13x = 65

Therefore, x = 65/14

X= 5. Put this value of 5 in equation 1, which gives;

15 + 2y = 39

2y = 39-25

2y = 24

Y = 12

Answer 2

x=5

y = 12

Explanation:

3x + 2y = 39

2y = 39 - 3x

y = (39 - 3x) / 2

5x - y = 13

5x - ((39 - 3x) / 2) = 13

5x - 39/2 + 3/2x = 13

5x + 3/2x = 13 + 39/2

13/2x = 65/2

x = 65/2 * 2/13

x = 65/13

x = 5

y = (39 - 3x) / 2

y = (39 - 3*5) / 2

y = (39 - 15) / 2

y = 24/2

y = 12