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2 votes
What is the value of the product (3-2i)(3+2i)?
5
9+ 41
9-41
13

User ITiger
by
8.6k points

1 Answer

3 votes

Answer:

13

Explanation:

The given expression is (3-2i)(3-2i)

This is of the form (a-b)(a+b)

This is equivalent to
\[a^(2)-b^(2)\], where a = 3 and b=2i

=
\[3^(2)-(2i)^(2)\]

=
\[9-4i^(2)\]

But
\[i^(2) = -1\]

=
\[9-4*(-1)\]

=
\[9+4\]

=
\[13\]

Hence the value of the expression (3-2i)(3-2i) is 13.

User Tim Givois
by
8.5k points

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