Question

If the x-component of a force vector is 2.16 newtons and its y-component is 4.11 newtons, then what is its magnitude? F = newtons

Answer 1

Magnitude of resultant vector will be 4.643 N

Step-by-step explanation:

We have given x-component of the force vector is given
`F_(X)=2.16N`

And y component of the force vector is given
`F_(y)=4.11N`

We have to find the magnitude of resultant force F

Resultant force will be equal to vector sum of magnitude of x competent and y component of force vector

So F =
`√(F_X^2+F_Y^2)=√(2.16^2+4.11^2)=4.643N`

So magnitude of resultant vector will be 4.643 N