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A particle is moving in a plane with constant radial velocity \dot{r} = 2.11 m/s, having started at the origin. It also has a constant angular velocity \dot{\theta} = 2.55 rad/s. When the particle is 2.
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A particle is moving in a plane with constant radial velocity
\dot{r} = 2.11 m/s, having started at the origin. It also has a constant angular velocity
\dot{\theta} = 2.55 rad/s. When the particle is 2.64 m from the origin, what is the magnitude of its velocity in m/s?

User Arifa Chan
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1 Answer

3 votes

Answer:Magnitude of velocity =14.20m/s

Step-by-step explanation:

The equation for the magnitude of velocity is given by:

/V/= SQRT r^2 +r^2×angular velocity ^2

/V/ = SQRT 2.11^2+ 2.64^2+2.55^2

/V/= SQRT 4.4521 + (6.9696 ×6.5025)

/V/=SQRT 201.768

/V/=14.20m/s

User Ahmad Kayyali
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