Question

What is the value of x in the equation below?

Answer 1

Explanation:

Alright, lets get started.

The given equation is :

`1+2e^(x+1)=9`

Subtracting 1 in both sides

`1+2e^(x+1)-1=9-1`

`2e^(x+1)=8`

Dividing 2 in both sides

`e^(x+1)=(8)/(2)`

`e^(x+1)=4`

Taking log on both sides

`loge^((x+1))=log4`

`(x+1)loge=log4`

Plugging the value of log e as 1

`x+1=log4`

`x=log4-1` ..................... Answer

Hope it will help :)