Question

If no heat is lost to the surroundings, how much heat must be added to raise the temperature from 20.0 ∘C to 85.0 ∘C ?

Answer 1

Step-by-step explanation:

`C_(water)` = 4190 J/kg.K

`C_(Al)` = 910 J/Kg. K

`m_(Al)` = 1.50 kg

`m_(water)` = 1.80 kg

`Q_(added) = Q_(Al) + Q_(water)`

`=m_(Al) C_(Al)`ΔT +
`m_(water) C_(water)`ΔT

= (1.50)(910)(85.0-20)+(1.80)(4190)(85.0-20)

= 578,955 J

= 579 kJ