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What are the potential solutions

What are the potential solutions-example-1
User Gopika BG
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4.6k points

2 Answers

0 votes

Answer: x= -2 and x= -4

Explanation:

User Zmike
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4.8k points
2 votes

Answer:
x = -2 \ and \ x = -4

Explanation:

Alright, lets get started.

The given equation is :


2ln(x+3)=0

Using the property of logs :
If \ log_(a)m=n, \ then \ a^n=m

So using this property in our equation


e^0=(x+3)


(x+3)=e^0


x+3=1

Subtracting 3 in both sides


x+3-3=1-3


x=-2

There is only one option with x as -2, hence part b is the answer. .......Answer

Hope it will help :)

User Raedwald
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4.9k points